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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 20°C to 80°C.
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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 20°C to 80°C.

User Momergil
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Answer: c is approximately .42J/g°C

Explanation: Your equation is q=mc️T (p.s sorry for the weird triangle... i dont have a delta symbol). Plug heat absorbed or lost into q, plug mass into m, place c in ( ), and plug temperature change into delta T. To find temperature change subtract 20°C from 80°C to get 60°C. Use order of operations to get c alone, and then you'll have your answer.

What is the specific heat of a substance that absorbs 2500 joules of heat when a sample-example-1
User Shounak Bose
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