Evaluate y=x squared minus 2x plus one for 3i

Question

asked Oct 18, 2020 121k views

1 Answer

Martinffx · Answer 1 · 2020-10-24T19:57:11+0000

Answer:

- 8 - 6i

Explanation:

The given expresion is

$y = {x}^(2) - 2x + 1$

We want to evaluate this expression when x=3i

We substitute to obtain:

$y = {(3i)}^(2) - 2(3i) + 1$

We simplify to get

$y = {3}^(2) * {i}^(2) - 6i + 1$

Recall that

${i}^(2) = - 1$

This implies that:

y = 9 * - 1 - 6i + 1

y = - 9 - 6i + 1

y = - 8 - 6i