Question

Evaluate y=x squared minus 2x plus one for 3i

Answer 1

`- 8 - 6i`

Explanation:

The given expresion is

`y = {x}^(2) - 2x + 1`

We want to evaluate this expression when x=3i

We substitute to obtain:

`y = {(3i)}^(2) - 2(3i) + 1`

We simplify to get

`y = {3}^(2) * {i}^(2) - 6i + 1`

Recall that

`{i}^(2) = - 1`

This implies that:

`y = 9 * - 1 - 6i + 1`

`y = - 9 - 6i + 1`

`y = - 8 - 6i`