Question

The centers of a 10 kg lead ball and a 60 g lead ball are separated by 15cm. Part A What gravitational force does each exert on the other? Express your answer in newtons.

Answer 1

`1.78*10^(-9)N`

Step-by-step explanation:

Because we know that the forces of one onto the other will be the same, we can use the equation:

`F_(1on2) =F_(2on1) = (Gm_(1) m_(2))/r^(2)`

G is the constant, 6.67 x 10^-11

Plugging, we get:

`((6.67*10^(-11))(10kg)(0.060kg))/(0.015m^(2) )`

=
`1.78*10^(-9)N`

Answer 2

`1.78\cdot 10^(-9)N`

Step-by-step explanation:

The magnitude of the gravitational force between two objects is given by

`F=G(m_1 m_2)/(r^2)`

where

`G=6.67\cdot 10^(-11) m^3 kg^(-1)s^(-2)` is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

For the balls in this problem,

`m_1 = 10 kg\\m_2 = 60 g = 0.06 kg\\r = 15 cm = 0.15 m`

Substituting into the equation, we find the gravitational force that each ball exerts on the other:

`F=(6.67\cdot 10^(-11))((10)(0.06))/((0.15)^2)=1.78\cdot 10^(-9)N`