Answer:
For figure 1:
Area of rectangle = 7x + 21
For figure 2:
Area of rectangle =
![\mathbf{p^2-9p }](https://img.qammunity.org/2022/formulas/mathematics/college/1jxzpr4n6543erk11nus5n8zhd401aue15.png)
Explanation:
We need to find area of rectangle
The formula used is:
![Area\:of\:rectangle=Length* Width](https://img.qammunity.org/2022/formulas/mathematics/college/eqyx46g3uepqm0b8mhhq35savg7f26tam9.png)
For figure 1:
Length = 7
Width = x+3
Putting values in formula and finding area of rectangle
![Area\:of\:rectangle=Length* Width\\Area\:of\:rectangle=7* (x+3)\\Now,\: multiply\:7\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=7(x)+7(3)\\Area\:of\:rectangle=7x+21\\](https://img.qammunity.org/2022/formulas/mathematics/college/amh1o5kbhyhs45xksnaycgxwgd97q393hd.png)
So, area of rectangle = 7x + 21
For figure 2:
Length = p
Width = p-9
Putting values in formula and finding area of rectangle
![Area\:of\:rectangle=Length* Width\\Area\:of\:rectangle=p* (p-9)\\Now,\: multiply\:p\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=p(p)-p(9)\\Area\:of\:rectangle=p^2-9p\\](https://img.qammunity.org/2022/formulas/mathematics/college/rpptvhl3ng8mpro79dl9ygrwt304v0op1z.png)
So, area of rectangle =
![\mathbf{p^2-9p }](https://img.qammunity.org/2022/formulas/mathematics/college/1jxzpr4n6543erk11nus5n8zhd401aue15.png)