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102 - Harder brackets

Find an expression without brackets
for the area of each rectangle.
(x + 3)
area =
12)
No
calc
р
(-9)
Total
area =
121​

102 - Harder brackets Find an expression without brackets for the area of each rectangle-example-1
User Felix Fung
by
5.7k points

1 Answer

12 votes

Answer:

For figure 1:

Area of rectangle = 7x + 21

For figure 2:

Area of rectangle =
\mathbf{p^2-9p }

Explanation:

We need to find area of rectangle

The formula used is:
Area\:of\:rectangle=Length* Width

For figure 1:

Length = 7

Width = x+3

Putting values in formula and finding area of rectangle


Area\:of\:rectangle=Length* Width\\Area\:of\:rectangle=7* (x+3)\\Now,\: multiply\:7\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=7(x)+7(3)\\Area\:of\:rectangle=7x+21\\

So, area of rectangle = 7x + 21

For figure 2:

Length = p

Width = p-9

Putting values in formula and finding area of rectangle


Area\:of\:rectangle=Length* Width\\Area\:of\:rectangle=p* (p-9)\\Now,\: multiply\:p\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=p(p)-p(9)\\Area\:of\:rectangle=p^2-9p\\

So, area of rectangle =
\mathbf{p^2-9p }

User Thedric Walker
by
5.0k points