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A person of Mass 50kg is on a swing which has the speed 10m,/s at the lowest point of the motion the ropes of the swing are 2.5m long.find the tension in the ropes​

1 Answer

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Answer:

T = 2490 newton

Step-by-step explanation:

Given that,

Mass of a person, m = 50 Kg

Speed of the swing at the lowest point, v = 10 m/s

Length of the rope, r = 2.5 m

Tension formula is given by

T = mg + ma N

where, T - Tension in the string

m - mass of the body

g - acceleration due to gravity

a - acceleration of the body

Since the person is swinging, the acceleration of the body is given by

a = v²/r m/s²

= 10/2.5 m/s²

a = 40 m/s²

Substituting in T

T = 50 Kg x 9.8 m/s² + 50 Kg X 40 m/s²

= 490 + 2000 Kg m/s²

T = 2490 newton

Therefore the tension in the rope is 2490 newton

User DmitryKanunnikoff
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