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How many grams are in 8.200 x 10^22 molecules of N216?

N2l6
O A) 1.27x 10-25
O
B) 21.09
O C) 4.94 x 10^46
OD) 3.19 x 10^44
O E) 9.33 x 10-25

1 Answer

2 votes

Answer:

107.23 g N₂I₆

Step-by-step explanation:

We are given 8.200 x 10^22 molecules of N₂I₆

Required to determine the mass of 8.2 x 10^22 molecules of N₂I₆

We will use the following steps:

Step 1: Number of moles of N₂I₆

Using the Avogadro's constant;

1 mole of a compound contains 6.022 × 10^23 molecules

Therefore;

8.200 x 10^22 molecules of N₂I₆ will have ;

= 8.200 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole

= 0.136 mole

Thus, number of moles of N₂I₆ is 0.136 mole

Step 2: Mass of 8.200 x 10^22 molecules of N₂I₆

Moles of 8.200 x 10^22 molecules of N₂I₆ is 0.136

But;

Mass = moles × molar mass

Molar mass of N₂I₆ = 789.44 g/mol

Therefore;

Mass = 0.136 mole × 789.44 g/mol

= 107.36 g N₂I₆

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