Answer:
107.23 g N₂I₆
Step-by-step explanation:
We are given 8.200 x 10^22 molecules of N₂I₆
Required to determine the mass of 8.2 x 10^22 molecules of N₂I₆
We will use the following steps:
Step 1: Number of moles of N₂I₆
Using the Avogadro's constant;
1 mole of a compound contains 6.022 × 10^23 molecules
Therefore;
8.200 x 10^22 molecules of N₂I₆ will have ;
= 8.200 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole
= 0.136 mole
Thus, number of moles of N₂I₆ is 0.136 mole
Step 2: Mass of 8.200 x 10^22 molecules of N₂I₆
Moles of 8.200 x 10^22 molecules of N₂I₆ is 0.136
But;
Mass = moles × molar mass
Molar mass of N₂I₆ = 789.44 g/mol
Therefore;
Mass = 0.136 mole × 789.44 g/mol
= 107.36 g N₂I₆