Question

what is the specific heat capacity of silver metal if 55.00g of the absored 47.3 calories of heat and temperature rise 15.°c​

Answer 1

`0.240 J/(g^(\circ)C)`

Step-by-step explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by
`\Delta T` according to the equation

`Q=mC_s \Delta T`

where

`C_s` is the specific heat capacity of the substance

In this problem, we have:

m = 55.0 g is the mass of the sample of silver

`Q = 47.3 \cdot 4.184 = 197.9 J` is the amount of energy supplied to the sample

`\Delta T = 15^(\circ)C` is the change in temperature of the sample

Solving the equation for
`C_s`, we find the specific heat capacity of silver:

`C_s = (Q)/(m \Delta T)=(197.9)/((55.0)(15))=0.240 J/(g^(\circ)C)`