Question

What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

Answer 1

Explanation:

Given

`y=x^2`

comparing it with standard equation
`x^2=4ay`

so 4a=1

`a=(1)/(4)`

so Focus of parabola is (0,0)

directrix

y=-a

here
`a=(1)/(4)`

`y=-(1)/(4)`