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Use the given values of logb(2), logb(3), and logb(5) to evaluate the following logarithms:

logb(10)

User Jenhan
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1 Answer

3 votes

Answer:

solved

Explanation:


log_b2= 0.3869


log_b3= 0.6131


log_b5= 0.8982

we now that


log_b10= log_b(2*5)


log_b10= log_b2 +log_b5


log_b10= 0.3869 +0.8982


log_b10=1.2851

User Shkelzen
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