Answer:
![3 + (2)/(log_(10)5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z6a3yny5wz3h3zfyro0hheqphlsaq9e7sq.png)
Explanation:
given,
log₅ (12500)
using logarithmic identity
logₐ a = 1
logₐ x³ = 3 logₐ x
log (ab) = log a + log b
logₐ x =
![(1)/(log_x a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/371r36uhnmyedy2722v6dtdtz5p9kqzgcg.png)
now,
log₅ (12500)
log₅ (5³ × 100 )
log₅ (5³) + log₅(100)
3 log₅ (5) + log₅ (10²)
3 + 2 log₅ (10)
![3 + (2)/(log_(10)5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z6a3yny5wz3h3zfyro0hheqphlsaq9e7sq.png)
hence, the required solution is given above.