Answer:
a. Pia´s age is 40.
b. The age of the woman is 43 and the age of the son is 8
c. The age of the woman is 27 and the age of the daughter is 3.
d. The consecutive integers are 16, 17 and 18.
Explanation:
You can solve these problems using easiest formulas thus.
a. Where Pia's age is X, could be expressed as: X + 16 That is the same than 2×(X-12). Thus:
X+16 = 2×(X-12)
X+16 = 2X-24
40 = X. Thus, Pia´s age is 40
b. The age of the woman is X and the age of the son is Y. Thus, X + Y = 51. Three years ago, the woman was eight times as old as her son. That means: X-3 = 8×(Y-3)
X+Y = 51; X = 51-Y
X-3 = 8×(Y-3)
X - 3 = 8Y - 24
8Y - 24 = (51 - Y) - 3
9Y = 72
Y = 8
X = 51- 8 = 43.
The age of the woman is 43 and the age of the son is 8.
c. The age of the Woman is X and the age of the Daughter is Y. In five years. X + Y = 40, that's the same than X+5 + Y+5 = 40. X - Y = 24.
Thus
X + Y = 30; Y = 30-X
X - Y = 24
X - (30-X) = 24
2X = 54
X = 27
27 - 24 = 3 = Y.
The age of the woman is 27 and the age of the daughter is 3.
d. Five three consecutives integers that sum 51 means.
X + (X+1) + (X+2) = 51
3X + 3 = 51
3X = 48
X = 16
X+1 = 17
X+2 = 18
The consecutive integers are 16, 17 and 18
I hope it helps!