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Given: △ABC, m∠A=60°,

m∠C=45°, AB=9
Find: Perimeter of △ABC,
Area of △ABC

Given: △ABC, m∠A=60°, m∠C=45°, AB=9 Find: Perimeter of △ABC, Area of △ABC-example-1

1 Answer

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Answer:

  • perimeter = 4.5(3+√3 +√6) ≈ 32.3169
  • area = 10.125(3+√3) ≈ 47.9120

Explanation:

Drawing an altitude (BD) from B to AC can be very helpful. It divides this triangle into two that have side ratios you recognize.

A 30°-60°-90° triangle has side ratios 1 : √3 : 2, and a 45°-45°-90° triangle has side ratios 1 : 1 : √2.

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The given side of 9 is the longest side of a 30-60-90 triangle, and the side AD is the shortest, so is 1/2 of 9, or 4.5. Side BD is the intermediate length of that triangle, so is 4.5√3.

The other leg of triangle BDC is the same length, so DC = 4.5√3. The hypotenuse of that triangle, BC, is √2 times that, or 4.5√6.

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Now, we know the three sides are 9, (4.5+4.5√3), and 4.5√6. The perimeter is the sum of these, or ...

P = 9 + 4.5 + 4.5√3 + 4.5√6

P = 4.5(3 +√3 +√6) ≈ 32.3169

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The area is given by the formula ...

A = 1/2bh

where the base length (b) is 4.5(1+√3), and the height is 4.5√3. Putting these values into the formula gives ...

A = 1/2(4.5(1+√3))(4.5√3)

A = 10.125(3+√3) ≈ 47.9120

Given: △ABC, m∠A=60°, m∠C=45°, AB=9 Find: Perimeter of △ABC, Area of △ABC-example-1
User Jonahb
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