Question

Trained dolphins are capable of a vertical leap of 7.0m straight up from the surface of the water-an impressive feat.Suppose you could train a dolphin to launch itself out of the water at this same speed but at an angle.What maximum horizontal range could the dolphin achieve?

Answer 1

θ = 45º

Step-by-step explanation:

To find the solution, let's use the projectile launch equation

R = vo² sin 2θ / g

Where vo is the initial speed of the dolphin, T is the angle of the jump and g the gravity acceleration.

To obtain a maximum range, the sine T function must be 1,

sin 2θ = 1

2θ = sin⁻¹ 1

2θ = 90

θ = 45º

Therefore, the dolphin should jump at an angle of 45º from the horizontal