Question

£65 of candy was divided into 4 different boxes the 2nd Box contained twice the amount of the 1st Box the 3rd Box contained a to more pounds than the 1st Box the last Box contain 1/4 the amount in the 2nd Box how much candy was in each Box

Answer 1

The fourth box contains 7 candies

Solution:

Let us assume that the first box contains x amount

The second box contain twice of first box that is = 2x

The third box contains two pound more than the first box that is = (x+2)

The last box contains
`(1)/(4)` the amount in the 2nd Box is
`\left((1)/(4) * 2 x\right)=\left((x)/(2)\right)`

Now the total candy in the box = 65

So we can say,

`x+2 x+(x+2)+\left((x)/(2)\right)=65`

`\Rightarrow 4 x+\left((x)/(2)\right)=65-2`

`\Rightarrow 4 x+\left((x)/(2)\right)=63`

`\Rightarrow 8 x+x=63 * 2`

`\Rightarrow 9 x=63 * 2`

`\Rightarrow \quad x=(63 * 2)/(9)=14`

So, first box contains 14 candy

Second box contains
`(2*14) =28 candy`

The third box contain
`(14+2) =16 candy`

The fourth box contains
`\left((14)/(2)\right)=7`