Question

Find the value of k so that the point A (5, 6) belongs to the graph of the following equation:

2y+kx=5.

Answer 1

2*6+k*5=5

12+5k=5

5k=5-12

5k=-7

k=-7/5

Answer 2

Answer: k= -1.4

Explanation:

To find : The value of k so that the point A (5, 6) belongs to the graph of the equation 2y+kx=5.

For that , we substitute (x,y) = (5,6) i.e. x= 5 and y=6 , we get

`2(6)+k(5)=5\\\\\Rightarrow\ 12+5k=5`

Subtract 12 from both the sides ,we get

`5k=-7\\\\\Rightarrow\ k=(-7)/(5)=-1.4` (Divide both sides by 5)

Hence, the required value of k= -1.4