Question

A rocket is fired at 100 m/s at an angle of 37, what was its total speed when it landed?

Answer 1

100 m/s

Step-by-step explanation:

Let find the velocity components first

Fx = 100 * cos (37) = 79.86 m/s

Fy = 100 * sin (37) = 60.18 m/s

applying motion equations

• Horizontal motion

assuming no acceleration in horizontal direction we can assure that the ending velocity component will still remain Fx = 79.86 m/s

• Vertical motion (upwards)

V² = U² +2as

= 60.18² + 2*(-10)*0

Fy = 60.18 m/s

Total speed = √(F²x+F²y) = 100 m /s

*** You can take the same answer considering the Energy