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A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectional area 40 mm2 and an unstretched length of 43 cm.

The truck begins stopped at a red light on a state highway. While stopped, the block hangs straight down to a distance 53 cm below the hook that attaches the bungee cord to the ceiling of the truck.

(a) What is the Young's modulus of the cord?

1 Answer

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Answer:


Y = 2.27 * 10^(10) N/m^2

Step-by-step explanation:

Natural length of the string is given as


L_o = 43 cm

length of the string while block is hanging on it


L = 53 cm

extension in length is given as


\Delta L = 10 cm

now we have strain in the string is given as


strain = (\Delta L)/(L)


strain = \frac{{10 cm}{43 cm}


strain = 0.23

similarly we will have cross-sectional area of the string is given as


A = 40 * 10^(-6) m^2

now the stress in the string is given as


Stress = (T)/(A)


Stress = (mg)/(A)


Stress = (3.7 * 9.81)/(40 * 10^(-6))


stress = 9.07 * 10^5 N/m^2

Now Young's Modulus is given as


Y = (stress)/(strain)


Y = (9.07 * 10^5)/(40* 10^(-6))


Y = 2.27 * 10^(10) N/m^2

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