Final answer:
By setting up a system of linear equations based on the given admission prices and total collected fees, we find that there were 184 children and 150 adults admitted to the amusement park.
Step-by-step explanation:
The student is dealing with a system of linear equations. We have two unknowns: the number of children and the number of adults who entered an amusement park. The admission fee for children is $1.50, and for adults, it is $4. We know that a total of 334 people entered the park, and the total admission fees collected amounted to $876.00.
Let's denote the number of children as c and the number of adults as a. We can set up the following equations:
c + a = 334 (the total number of people)
1.50c + 4a = 876 (the total amount of money collected)
To solve these equations, we can use either substitution or elimination methods. We will use the elimination method. Multiplying the first equation by 1.50 gives us another equation 1.50c + 1.50a = 501. Now, we subtract this new equation from the second equation in our system to eliminate c:
1.50c + 4a = 876
- (1.50c + 1.50a = 501)
The result is:
2.50a = 375
Dividing both sides by 2.50, we find that:
a = 150
Substituting this value for a into the first equation, we have:
c + 150 = 334
Therefore, c = 334 - 150 = 184.
So, there were 184 children and 150 adults admitted to the amusement park.