Question

[Ni(NH)]2+ forms a blue solution. Estimate the crystal field splitting energy (in kJ/mol) if the wavelength of maximum absorption is 455 nm. a) 2.63 x 105 b) 4.37 x 10-19 c) 263 d) 2.63 x 10-7 e) 4.37 x 10-28

Answer 1

The correct answer is option c.

Step-by-step explanation:

Wavelength absorbed by the
`[Ni(NH_3)_4]^(2+)=\lambda =455nm`

Energy of the radiation = E

`E=(hc)/(\lambda )`

h = Planck's Constant , c= speed of the light

`E=(6.626* 10^(-34) Js* 3* 10^8 m/s)/(4.55* 10^(-7) m)=4.3688* 10^(-19) J`

`1 mol = N_A=6.022* 10^(23)` particles

The crystal field splitting energy :

`=E* N_A=4.3688* 10^(-19) J* 6.022* 10^(23) mol^(-1)`

`=263,088.60 J/mol=263.08860 kJ/mol\approx 263 kJ/mol`