Question

Find the force on a 5 pС charge in a place where the electric field is 400 N/C.

Answer 1

Electric force,
`F=2* 10^(-9)\ N`

Step-by-step explanation:

It is given that,

Charge on the particle,
`q=5\ pC=5* 10^(-12)\ C`

Electric field,
`E=400\ N/C`

Let F is the electric force acting on the charged particle. The electric force per unit electric charge is called electric field. Mathematically, it is given by :

`F=qE`

`F=5* 10^(-12)\ C* 400\ N/C`

`F=2* 10^(-9)\ N`

So, the force acting on the charged particle is
`2* 10^(-9)\ N`. Hence, this is the required solution.