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Consider a region of space with volume 48 mm^3. Suppose the energy stored in the electric field of that particular region of space is 50 J. What is the average electric field strength in this region?

1 Answer

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Answer:

Electric field,
E=1.53* 10^(10)\ N/C

Step-by-step explanation:

It is given that,

Volume of the space,
V=48\ mm^3=4.8* 10^(-8)\ m^3

The energy stored in the electric field, U = 50 J

We know that the stored energy in the electric field per unit volume of given by :


(U)/(V)=(1)/(2)\epsilon_o E^2

E is the electric field in this region.


E=\sqrt{(2U)/(\epsilon_o V)}


E=\sqrt{(2* 50)/(8.85* 10^(-12)* 4.8* 10^(-8))}


E=1.53* 10^(10)\ N/C

Hence, this is the required solution.

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