Question

A constant net force that has a magnitude of 135.5 N is exerted on a 26.7 kg object that is initially not moving. a. Draw a free body diagram of the object. Assume there is only the net force of 135.5 N acting on the object.

b. What acceleration does this force produce?
c. Sketch a position vs. time graph for the object.
d. Sketch a velocity vs.. time graph for the object.
e. How far does the the object travel in 8.82 s?

Answer 1

Step-by-step explanation:

Given that,

Net force = 135.5 N

Mass = 26.7 kg

(a). We need to draw a free body diagram

A force is exerted on a object.

(b). We need to calculate the acceleration

Using formula of acceleration

`a =(F)/(m)`

`a=(135.5)/(26.7)`

`a=5.07\ m/s^2`

(c). We need to draw the sketch a position vs. time graph for the object.

Using equation of motion

`s=ut+(1)/(2)at^2`

Put the value into the formula

`s=0+(1)/(2)*5.07* t^2`

`s=2.535 t^2`

(d). We need to draw the sketch a velocity vs. time graph for the object.

Using equation of motion

`v = u+at`

Put the value into the formula

`v=0+5.07t`

`v =5.07 t`

(e). We need to calculate the distance travel in 8.82 s

Using equation of motion

`s=ut+(1)/(2)at^2`

`s=0+(1)/(2)*5.07*(8.82)^2`

`s=197.20\ m`

Hence, This is the required solution.