Answer:
Let a and b integers and suppose that are even numbers. Then, exist integers k and m such that
and
.
Then,
![a+b=2k+2m=2(k+m)=2n](https://img.qammunity.org/2020/formulas/mathematics/college/3yv6g6ki23ivfw4mjgcvfwmw775orgzofe.png)
Since, k and m are integers then n=k+m is an integer. Then, since a + b is of the form 2 by an integer n, then a + b is an even number.