Question

the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 46 meters and its length is 2 meters more than twice its width

Answer 1

The length of rectangle is 16 meters and the width of rectangle is 7 meters

Explanation:

Let

L -----> the length of the rectangle

W ---> the width of the rectangle

we know that

The perimeter of rectangle is equal to

`P=2(L+W)` ----> the perimeter of a rectangle is twice the sum of its length and its width

we have

`P=46\ m`

so

`46=2(L+W)`

simplify

`23=(L+W)` -----> equation A

`L=2W+2` ----> equation B

substitute equation B in equation A and solve for W

`23=(2W+2+W)`

`23=3W+2`

`3W=23-2`

`3W=21`

`W=7\ m`

Find the value of L

`L=2(7)+2=16\ m`

therefore

The length of rectangle is 16 meters and the width of rectangle is 7 meters