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find all numbers such that a third of a number increased by half that number is at least 3 less than that same number

User JPro
by
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1 Answer

2 votes

Answer:

All real numbers less than or equal to 18

Explanation:

Let

x -----> the number

we know that

The algebraic expression that represent this situation is


(1)/(3)x+(1)/(2)x \geq x-3

Solve for x

Multiply by 6 both sides to remove the fractions


2x+3x \geq6x-18

Combine like terms left side


5x \geq6x-18

Adds 18 both sides


5x+18 \geq 6x

Subtract 5x both sides


18 \geq 6x-5x


18 \geq x

Rewrite


x\leq 18

All real numbers less than or equal to 18

User Swadhikar
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