Answer:
0.0901
Step-by-step explanation:
Let us assume 100 people have disease in the question
which is 0.1% of the total population. therefore, total population will be 100000.
now 99.9% of the population does not have the disease which is 100000-100= 99900.
from 100 people diseased people, 99 test positive, and 1 negative.
and from the 99900 of the non diseased people, 999 will be diagnosed diseased and 99900-999= 98,901 will be diagnosed non diseased
so, total number of people tested positive are 99+999= 1098
out of these many people only 99 people actually of the disease
what is the conditional probability that he/she does, in fact, have the disease=
99/1098= 0.0901