Question

A 0.907 mole sample of ideal gas at 12C occupies a volume of 4.25L. What is the pressure of gas?

Answer 1

4.99atm

Step-by-step explanation:

PV=nRT

P= nRT/V

V= 4.25L

T= 12 C = 285.15 kalvin

n= 0.907 mol

R= 0.082057 L⋅atm/mol⋅K

P= (0.907)(0.082057)(285.15)/(4.25)= 4.9935 atm