Question

A 24.7-g bullet is fired from a rifle. It takes 2.73 × 10-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 784 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

Answer 1

`F_a_v_g=7093333.33N*s`

Step-by-step explanation:

The impulse or average force in classical mechanics is the variation in the linear momentum that a physical object experiences in a closed system. It is defined by the following equation:

`F_a_v_g=m*(\Delta v)/(\Delta t)=m*(v_2-v_1)/(t_2-t_1)`

Where:

`m=mass\hspace{3}of\hspace{3}the\hspace{3}object`

`v_2=final\hspace{3}velocity\hspace{3}of\hspace{3}the\hspace{3}object\hspace{3}at\hspace{3}the\hspace{3}end\hspace{3}of\hspace{3}the\hspace{3}time\hspace{3}interval`

`v_1=initial\hspace{3}velocity\hspace{3}of\hspace{3}the\hspace{3}object\hspace{3}when\hspace{3}the\hspace{3}time\hspace{3}interval\hspace{3}begins.`

`t_2=final\hspace{3}time`

`t_1=initial\hspace{3}time`

Asumming v1=0 and t1=0:

`F_a_v_g=m* (v_2)/(t_2) =(24.7)*(784)/(2.73*10^(*3) ) =7093333.333N*s`