Question

A train travels due south at 24 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of each raindrop makes an angle of 70° with the vertical, as measured by an observer stationary on the ground. An observer on the train, however, sees the drops fall perfectly vertically. Determine the speed of the raindrops relative to the ground.

Answer 1

`N_(Rain)=25.54 m/s`

Step-by-step explanation:

given,

train travels due south at = 24 m/s

rain blown toward south

path of raindrop = 70° with vertical

so,

now,

`\vec{N_(PO)}=\vec{N_(PO')}+\vec{N_(O'O)}`

`N_(PO)_x=N_(PO')_x+N_(1'O)_x`

`N_(R)sin \theta = 0 + N_(train)`

`N_(R)=(N_(train))/(sin \theta)`

`N_(R)=(24)/(sin70^0)`

`N_(Rain)=25.54 m/s`