Question

if an object accelerates from rest what will its velocity be after 12.3 s if it has a constant acceleration of 4.6 m/s

Answer 1

56.6 m/s

Step-by-step explanation:

The velocity of an object accelerating at constant acceleration is given by the following SUVAT equation

`v(t)=u+at`

where

u is the initial velocity

a is the acceleration

t is the time

For the object in the problem,

u = 0 since it starts from rest

`a=4.6 m/s^2` is the acceleration

Substituting t = 12.3 s, we find the velocity at that time:

`v=0+(4.6)(12.3)=56.6 m/s`