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Assume the exponential growth model ​A(t)=A subscript 0 e superscript kt and a world population of 6.7 billion in 2005. If the population must stay below 21billion during the next 100​ years, what is the maximum acceptable annual rate of​ grow

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Answer:

0.010423315 x 109 = 1.04 x 107 people

Explanation:

(19 x 109) = (6.7 x 109) (e100k)

and solve for k

(19 x 109) / (6.7 x 109) = e100k

2.835820896 = e100k

ln 2.835820896 = ln e100k

ln 2.835820896 = 100k

k = (ln 2.835820896) / 100

User Viktor Eriksson
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