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In triangle ABC, the measure of angle B is 35 degrees more than three times the measure of angle A. The measure of angle C is 57 degrees more than the measure of angle A. Find the measure of each angle.

What is the measure of angle A? _____
What is the measure of angle B? _____
What is the measure of angle C? _____

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Answer:

Explanation:

Given that in a triangle ABC, the measure of angle B is 35 degrees more than three times the measure of angle A.

Measure of C = 57 degrees more than measure of A


Angle C = Angle A +57

Measure of B = 35 degrees more than three times measure of A


Angle B = 35+3 (angle A)

Sum of three angles = 180

Hence if
Angle A = x, we get


x+x+57+3x+35 =180\\5x+92 =180\\5x =88\\x=17.6

Hence angles are


A =17.6^(o) B =87.8^(o)C=74.6^(o)

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