Question

5. An arresting device on a carrier deck stops an airplane in 1.5 s. The average acceleration was

49 m/s². a) What was the stopping distance? b) What was the initial speed?

Answer 1

See below

Step-by-step explanation:

(Using acceleration = - 49 m/s^2)

vf = vo + at

0 = vo + at

vo = - at

Distance ( or displacement) = do + vot + 1/2 at^2 <=====sub in vo = -at

= 0 + -at t + 1/2 at^2

d = - 1/2 a t^2 since a = - 49 m/s^2 d = -1/2 ( -49)(1.5^2) = 55.125 m

vf = vo + at

0 = vo + (-49)t = 73.5 m/s = vo

( I am not POSITIVE of this answer)