Answer:
0.64 g.
Step-by-step explanation:
Na2CO3 + H2SO4 ---> Na2SO4 + CO2 + H2O
82.99 g of Na2CO3 reacts with 98.07 g of H2SO4 to give 44 g of CO2
So 2 g of Na2CO3 gives a theoretical yield of (44 / 82.99) * 2 = 1.06g CO2
If the yield is 60.2% the actual yield is 1.06 * 0.602
= 0.64 g.