Answer:
Distance traveled will be 5.6307 m
Step-by-step explanation:
Time t = 3 sec
We have given force F = 25 N
We know that force is given by F = ma
So ma = 25 -----------eqn 1
Weight is given by W = 196 N
We know that weight is given by W = mg
So mg = 196 -----------------eqn 2
From equation 1 and equation 2
![(a)/(g)=(25)/(196)](https://img.qammunity.org/2020/formulas/physics/high-school/mh0y3vbt0edac3zueu0b7sslgoxwxw5wiu.png)
![a=1.2512m/sec^2](https://img.qammunity.org/2020/formulas/physics/high-school/fq82gqj8bg4e7047tdqmyfn085vjmoeaa3.png)
Initial velocity is given as 0 so u = 0 m/sec
From second equation of motion
![s=ut+(1)/(2)at^2=0* 3+(1)/(2)* 1.2512* 3^2=5.6307m](https://img.qammunity.org/2020/formulas/physics/high-school/lfkyrjulxex00la2lg27888sw0n4mlzkoy.png)