Question

The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine the length of the base, b, in meters. Then solve the equation.

Answer 1

`((2)A)/(h) =b`

b=0.00906m

Explanation:

Hello! To solve this exercise we must remember that the area of ​​any triangle is given by the following equation

`A=(bh)/(2)`

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of ​​a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

`A=(bh)/(2) \\(2)/(h) A=(bh)/(2) (2)/(h) \\`

`(A(2))/(h) =b`

solving

`(2(32.5))/(7172) =0.0090[tex](A(2))/(h) =b\\b=0.00906m`