Question

calculate the specific heat capacity for gold n 105 joules are required to heat 30.0 grams of gold from 27.7c to 54.9c

Answer 1

The specific heat capacity for gold in 105 joules which are required to heat 30.0 grams of gold is 0.129 J/(g℃)

Step-by-step explanation:

We make use of the formula

`Q=m * c * \Delta T`

where

∆T = final T - initial T

= 54.9℃ - 27.7℃ = 27.2℃

Q is the heat energy in Joules = 105J

c is the specific heat capacity = ?

m is the mass of Gold = 30.0g

`Q=m * c * \Delta T`

Rearranging the formula

`c= \frac {Q}{(m* \Delta T)}`

`= \frac {105J}{(30.0g * 27.2 ^\circ{C})}\\\\= \frac {105J}{(816g^\circ{C})}`

So,

c = 0.129 J/(g℃)

(Answer)