Answer:
0.006 mol of CaCl2 are present
Step-by-step explanation:
Use dimensional analysis for this:
60.0 mL CaCl2/1 * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol
If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.
**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.
Hope this helps :)