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4 votes
A line passes through 2, -1 and 4, 5 what is the equation

User Yoojung
by
6.1k points

2 Answers

5 votes

y1 - y2 / x1 - x2

-1 - 5 / 2 - 4

-6/-2

3

y = mx + b

-1 = 3(2) + b

-1 = 6 + b

-7 = b

y = 3x - 7

Hope this helps! ;)

User Christopheraue
by
6.2k points
0 votes

Answer:

The equation is
3x -y =7

Solution:

Let us assume that the
(x_1, y_1) = (4,5) and
(x_2, y_2) = (2,-1)

The slope of the line m is
=(y_2-y_1)/(x_2-x_1)=(-1-5)/(2-4)=\left((6)/(2)\right)=3

We know the equation of a line at a given point
(x_1,y_1) is (y-y_1) = m(x-x_1)

Let me take the point (4,5) here,

So the equation of the line is


(y-5)=3 *(x-4)


y-5=3 x-12


3x-12 - y+5 = 0


3x -y -7 =0


3x -y =7

So, the equation is
3x-y =7

User Rune Jacobsen
by
6.8k points
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