Question

Water boils at different temperatures at different elevations. The boiling temperature of water is 212degreesF at sea level​ (0 feet) but drops about 1.72degreesF for every​ 1,000 feet of elevation. Write a formula for the boiling point at a given elevation. Then solve the formula for the elevation when the boiling point for water is 190degreesF.

Determine a formula for the boiling point​ b, in degrees​ Fahrenheit, at elevation​ h, in feet.



PLEASE HELP ME I'M IN CLASS RIGHT NOW​

Answer 1

The elevation when the boiling point for water is 190 degrees Fahrenheit is approximately 12,790.7 feet.

Let's assume the boiling point of water at elevation h is represented by the variable b.

We know that at sea level (elevation h = 0), the boiling point is 212 degrees Fahrenheit.

We can express this mathematically as:

b = 212 - 1.72(h/1000)

where b is the boiling point in degrees Fahrenheit and h is the elevation in feet.

Now, we are asked to determine the elevation when the boiling point for water is 190 degrees Fahrenheit. In this case, we can plug b = 190 into the equation and solve for h:

190 = 212 - 1.72(h/1000)

Solving for h, we get:

h = 12790.7 feet

Therefore, the elevation when the boiling point for water is 190 degrees Fahrenheit is approximately 12,790.7 feet.

Answer 2

Formula:
`b=-0.00172h+212`

Elevation at 190 degrees is about 12,790.7 feet

Explanation:

since 1.72 degrees are lost for every 1000 feet, we can say:

for every feet, 1.72/1000 = 0.00172 degrees are lost. That is the slope of the function.

Now, to find the y-intercept, we need to know at elevation (h=0), how much is boiling point?

That is 212, so this is y-intercept.

The equation would be

y = mx + b

Where m is the slope and b is the y-intercept

So,

we can write:

y = -0.00172x+212

Changing variables:

b = -0.00172h + 212

To find elevation when boiling point is 190, we put 190 into b and solve for h:

190 = -0.00172h + 212

0.00172h = 22

h=12,790.7 feet