Answer:
![2*cos(2x+(\pi)/(4) )-2](https://img.qammunity.org/2020/formulas/mathematics/college/d7pmavi6b6eipciva6bqta74k9aj647l0k.png)
Explanation:
Recall the trigonometric definitions for the geometrical characteristics given to you:
For a General Harmonic function of the type:
![f(x)=A* cos(Bx+C)+D](https://img.qammunity.org/2020/formulas/mathematics/college/rwuntukholmj9px5r4drujjzi3dkrhnan6.png)
we define:
|A| = Amplitude of the function
Period of the function =
![(2\pi )/(B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/trqg6wet9kqp99zjbyutat04bs0iiup67c.png)
Phase shift =
![-(C)/(B)](https://img.qammunity.org/2020/formulas/mathematics/high-school/a3zqq394ch37zhq1wcfeaiv3t2ifa8lxri.png)
vertical shift = D
Therefore we can construct a function that includes the appropriate geometric characteristics requested by using:
A = 2
To find B we use the definition of period, and what value we want it to have:
![(2\pi )/(B)=\pi \\(2\pi )/(\pi)=B\\B=2](https://img.qammunity.org/2020/formulas/mathematics/college/kz5tcak68xc1pyc7xz5ysql1s1w6n55m1x.png)
To find C we use the definition of phase shift and the value we want it to have (also using the value for B we found in the step above):
![-(C)/(B)=-(\pi)/(8) \\-(C)/(2)=-(\pi)/(8)\\C=(2* \pi)/(8) =(\pi )/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/tzmpg4jok1y9fw1mscy6n7kw3coau81nmr.png)
and finally, D = -2
Therefore the function will look like:
![2*cos(2x+(\pi)/(4) )-2](https://img.qammunity.org/2020/formulas/mathematics/college/d7pmavi6b6eipciva6bqta74k9aj647l0k.png)