Question

The question asks to find all real values of x for which f(x)=0.

Answer 1

Explanation:

40.

f(x)=x^2-6x-16

=x^2-8x+2x-16

=x(x-8)+2(x-8)

=(x-8)(x+2)

for root

f(x)=0

(x-8)(x+3)=0

x=8 or -3

41.

=x^3-x

=x(x^2-1)

=x(x+1)(x-1)

for root

x(x+1)(x-1)=0

x=0,1,-1

42.

=x^3-x^2-3x+3

=x^2(x-1)-3(x-1)

=(x-1)(x^2-3)

for root

(x-1)(x^2-3)=0

x=1,-√3,√3