Answer:
The metal rod cannot fit into the rectangular crate
The maximum length that can fit is 2.71 m
Explanation:
step 1
Find the diagonal of the base of the rectangular crate
Applying the Pythagoras Theorem
Let
d ----> the diagonal of the base
![d^2=0.8^2+1.2^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1t62dtzubelbxiotewewi1vw0e6m3gz85u.png)
![d^2=2.08](https://img.qammunity.org/2020/formulas/mathematics/middle-school/80bd73rrl81frtlu9ufjw9pomk8pjfhho7.png)
![d=1.44\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l5qeb3wvuea3vk133km1dko06i4ii3p2i5.png)
step 2
Find the diagonal of the crate
Let
D ----> the diagonal of the crate
![D^2=d^2+h^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iidig9grypy3qshq2pqsr8fmc8stjjc389.png)
where
d is the diagonal of the base
h is the height of the crate
we have
![d=1.44\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l5qeb3wvuea3vk133km1dko06i4ii3p2i5.png)
![h=2.3\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ol8ki5gm0nmr0pvkjg296ld258mt8nnh2q.png)
substitute the values
![D^2=1.44^2+2.3^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l4jfcse89q0q5619ljqyw6snex3qeuzpb8.png)
![D^2=7.36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/29yz55c1d8y2zawwybzp3dprv7z50uklgw.png)
![D=2.71\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3atls3rbdjtjoc5la3oznvhk1k9048hgnt.png)
therefore
The metal rod cannot fit into the rectangular crate
The maximum length that can fit is 2.71 m