Question

At a certain temperature, the rate constant for this reaction is 5.64×10−4 s−1 . Calculate the half-life of cyclopropane at this temperature.

Answer 1

`t_(1/2)= 20.47\ minute`

Step-by-step explanation:

given,

constant rate for the reaction(k) = 5.64 × 10⁻⁴ s⁻¹

to calculate the half life = ?

`t_(1/2) = (0.693)/(k)`

`t_(1/2) = (0.693)/(5.64* 10^(-4))`

on solving the above equation

`t_(1/2) = 1228.72 s`

`t_(1/2) = (1228.72)/(60)`

`t_(1/2)= 20.47\ minute`

hence, the half-life of cyclopropane at this temperature =
`t_(1/2)= 20.47\ minute`