Question

A 2.4 g sample of a mixture of calcium chloride, CaCl2, and sodium chloride, NaCl, is found to contain 0.12g Na. What percent of this sample is NaCl?

Answer 1

The percent of NaCl in the sample is calculated by converting the mass of sodium to the mass of NaCl and then finding the proportion of NaCl in the mixture. The result is that 12.71% of the sample is NaCl.

Step-by-step explanation:

To calculate the percent of NaCl in the mixture, we first need to find the mass of NaCl using the mass of sodium provided. Since sodium chloride consists of one atom of sodium and one atom of chlorine, and given the molar masses (sodium = 22.99 g/mol, chlorine = 35.45 g/mol), we can determine the mass of NaCl in the sample. The molecular mass of NaCl is 58.44 g/mol.

The calculation is as follows:

1. 
   
2. Find the moles of sodium: moles of Na = mass of Na / molar mass of Na = 0.12g / 22.99g/mol = 0.00522 mol.
3. 
   
4. Convert moles of sodium to moles of NaCl (since the ratio of Na to NaCl is 1:1, it's the same number of moles): moles of NaCl = 0.00522 mol.
5. 
   
6. Calculate the mass of NaCl: mass of NaCl = moles of NaCl * molar mass of NaCl = 0.00522 mol * 58.44 g/mol = 0.305 g.
7. 
   
8. Calculate the percent of NaCl in the mixture: (mass of NaCl / total mass of mixture) * 100 = (0.305 g / 2.4 g) * 100 = 12.71%.

Therefore, 12.71% of the sample is NaCl.

Answer 2

12.7% NaCl

Hello, I believe this question is talking about the mass percentage of sodium chloride and we must use stoichiometry and then divide by the total mass of the mixture

This is what I did


0.12g Na x 1/22.99 x 1NaCl/Na x 58.44/1

This will result in 0.305 grams

When then divide this by 2.4

0.305/2.4 = 0.127, then multiply by 100

12.7%