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The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were observed by Tycho Brahe and analyzed by Johannes Kepler. A good starting point for understanding this (as well as the speed of the space shuttle and the height of geostationary satellites) is the simplest orbit - a circular one. This problem concerns the properties of circular orbits for a satellite orbiting a planet of mass M. Use G for the universal gravitational constant. Find the orbital period T.

User BostonJohn
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Answer:

Step-by-step explanation:

We know that , for an object to remain in circular motion , a force towards centre is required which is called centripetal force. In the circular motion of

satellites around planet , this force is provided by the gravitational attraction between satellite and planet.

If M be the mass of planet and m be the mass of satellite, G be gravitational constant and R be the distance between planet and satellite or R be the radius of orbit

Gravitational force = G Mm / R²

If v be the velocity with which satellite is orbiting

centripetal force

= m v² /R

Centripetal force = gravitational attraction

m v² /R = G Mm / R²

v =
\sqrt{(GM)/(R) }

Time period = time the satellite takes to make one rotation

= distance / orbital velocity

= 2πR/ v

=
(2\pi R√(R) )/(√(GM) )

T =
(2\pi R^(3)/(2) )/(√(GM) )

User Ryan Weinstein
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