Answer:
Step-by-step explanation:
We know that , for an object to remain in circular motion , a force towards centre is required which is called centripetal force. In the circular motion of
satellites around planet , this force is provided by the gravitational attraction between satellite and planet.
If M be the mass of planet and m be the mass of satellite, G be gravitational constant and R be the distance between planet and satellite or R be the radius of orbit
Gravitational force = G Mm / R²
If v be the velocity with which satellite is orbiting
centripetal force
= m v² /R
Centripetal force = gravitational attraction
m v² /R = G Mm / R²
v =
![\sqrt{(GM)/(R) }](https://img.qammunity.org/2020/formulas/physics/college/kflslh4oot1bhep1k95vlhdys8x1eeephp.png)
Time period = time the satellite takes to make one rotation
= distance / orbital velocity
= 2πR/ v
=
![(2\pi R√(R) )/(√(GM) )](https://img.qammunity.org/2020/formulas/physics/college/z9izwrd7ay6nv48uxn7odyx69crank75gi.png)
T =
![(2\pi R^(3)/(2) )/(√(GM) )](https://img.qammunity.org/2020/formulas/physics/college/ebeko538x43ftvnhgq0f3x98jk6qu9a7e5.png)