Question

A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?

Answer 1

2.6645m

Step-by-step explanation:

applying motion equations we can find the answer,

`v^(2)=u^(2)  +2as`

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s = distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

`v^(2)=u^(2)  +2as\\0=7.3^(2) -2*10*s\\s=2.6645m`