What is the direction of the frictional force?
Answer:
Direction of friction is always opposite to relative motion
Step-by-step explanation:
Friction always resist the relative motion of two surface so it is always opposite to the direction of relative velocity
What is the direction of the normal force?
Answer:
It is perpendicular to the contact plane
Step-by-step explanation:
Normal force is the perpendicular force which is always at 90 degree with the contact surface
How does the frictional force depend on the normal force?
Answer:
![F_f = \mu F_n](https://img.qammunity.org/2020/formulas/physics/middle-school/m9c3khl2h1qyan0ytq8ouy1582vgofut4q.png)
Step-by-step explanation:
Friction force is directly proportional to the normal force so we can say it is given as
![F_f = \mu F_n](https://img.qammunity.org/2020/formulas/physics/middle-school/m9c3khl2h1qyan0ytq8ouy1582vgofut4q.png)
Let the x-axis be parallel to the incline and the y-axis rise from the incline at a right angle. By Newton's second law, if there is no acceleration in the y-direction (perpendicular to the plane), what must be the magnitude of the normal force?
Answer:
![F_n = mg cos\theta](https://img.qammunity.org/2020/formulas/physics/college/a9zrq3ca7ii4ros82mnghnnjc1siw1s839.png)
Step-by-step explanation:
Normal force is equal to the component of the weight opposite to the direction of normal force
![F_n = mg cos\theta](https://img.qammunity.org/2020/formulas/physics/college/a9zrq3ca7ii4ros82mnghnnjc1siw1s839.png)
Use Newton's second law and the x-components of the forces to find the acceleration. m/s2
Answer:
![a = gsin\theta](https://img.qammunity.org/2020/formulas/physics/college/n8i6wae8qmdmgd8xe5ck6yuayxtx4lanqu.png)
Step-by-step explanation:
As we know that
![F_(net) = ma](https://img.qammunity.org/2020/formulas/physics/high-school/ndgotbvij7522nqvxesuhb8y0a7dz9lzlt.png)
![mg sin\theta = ma](https://img.qammunity.org/2020/formulas/physics/high-school/ld1uo1fcc5ddhpprrcnoqubwdbzekq7ogr.png)
![a = gsin\theta](https://img.qammunity.org/2020/formulas/physics/college/n8i6wae8qmdmgd8xe5ck6yuayxtx4lanqu.png)