Answer:
![2* (x+y) > 70\\x \leq 30\\y\leq 20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/66y11rd4gnjqjehvoy3z6gj05f5hygah05.png)
c) (35,20) and (25,15)
Explanation:
We are given the following information in the question:
Let x be the length of the rectangle and y be the width.
Perimeter of rectangle =
![2* \text{(Length + Width)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ejkizzo10mdy80af4w288mcs8gtvnfrp5i.png)
a) Then, we can have the following inequalities:
![2* (x+y) > 70\\x \leq 30\\y\leq 20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/66y11rd4gnjqjehvoy3z6gj05f5hygah05.png)
b) The attached image shows the graph for the three inequalities.
c) The two possible combination of length and width of rectangle could be:
(35,20) and (25,15)
The points are shown in the graph and satisfies all the three inequalities.