An object is dropped from a building and strikes the ground with a speed of 44 m/s. How tall is the building? *

Dennycrane asked Nov 3, 2023

511,289 views

5 votes

Dennycrane asked Nov 3, 2023

2.9k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

13 votes

Answer:

d = 98.67m

Step-by-step explanation:

equation:

vf^2 = vi^2 + 2ad

(44m/s)^2 = (0m/s)^2 + 2(9.81m/s^2)(d)

1936m^2/s^2 = 19.62m/s^2(d)

divide both sides by 19.62m/s^2

d = 98.67m approximately

AXM answered Nov 8, 2023

by AXM

2.6k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers